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A+B = C / +2A
3A+B = C+2A /+(2B+2C)
3A+3B+2C = 3C+2A+2B
3A+3B-3C = 2A+2B-2C
3(A+B-C) = 2(A+B-C) /: (A+B-C)
3 = 2  |
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Last Post 2008-01-14, 04:20
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